Two circles ${{S}_{1}}={{x}^{2}}+{{y}^{2}}+2{{g}_{1}}x+2{{f}_{1}}y+{{c}_{1}}=0$ and ${{S}_{2}}={{x}^{2}}+{{y}^{2}}+2{{g}_{2}}x+2{{f}_{2}}y+{{c}_{2}}=0$ cut each other orthogonally, then

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Accepted Answer

$2{{g}_{1}}{{g}_{2}}+2{{f}_{1}}{{f}_{2}}={{c}_{1}}+{{c}_{2}}$

Answer

$2{{g}_{1}}{{g}_{2}}-2{{f}_{1}}{{f}_{2}}={{c}_{1}}+{{c}_{2}}$

Answer

$2{{g}_{1}}{{g}_{2}}+2{{f}_{1}}{{f}_{2}}={{c}_{1}}-{{c}_{2}}$

Answer

$2{{g}_{1}}{{g}_{2}}-2{{f}_{1}}{{f}_{2}}={{c}_{1}}-{{c}_{2}}$

circle

Question: Two circles ${{S}_{1}}={{x}^{2}}+{{y}^{2}}+2{{g}_{1}}x+2{{f}_{1}}y+{{c}_{1}}=0$ and ${{S}_{2}}={{x}^{2}}+{{y}^{2}}+2{{g}_{2}}x+2{{f}_{2}}y+{{c}_{2}}=0$ cut each other orthogonally, then

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