circle

Question: Two given circles ${{x}^{2}}+{{y}^{2}}+ax+by+c=0$ and ${{x}^{2}}+{{y}^{2}}+dx+ey+f=0$ will intersect each other orthogonally, only when



1) $a+b+c=d+e+f$
2) $ad+be=c+f$
3) $ad+be=2c+2f$
4) $2ad+2be=c+f$
Solution: Explanation: No Explanation
System of circles

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