circle

Question: A circle is concentric with the circle ${{x}^{2}}+{{y}^{2}}-6x+12y+15=0$ and has area double of its area. The equation of the circle is



1) ${{x}^{2}}+{{y}^{2}}-6x+12y-15=0$
2) ${{x}^{2}}+{{y}^{2}}-6x+12y+15=0$
3) ${{x}^{2}}+{{y}^{2}}-6x+12y+45=0$
4) None of these
Solution: Explanation: No Explanation
Equations of circle Geometrical problems regarding circle

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