circle

Question: A circle passes through the origin and has its centre on $y=x$ . If it cuts ${{x}^{2}}+{{y}^{2}}-4x-6y+10=0$ orthogonally, then the equation of the circle is



1) ${{x}^{2}}+{{y}^{2}}-x-y=0$
2) ${{x}^{2}}+{{y}^{2}}-6x-4y=0$
3) ${{x}^{2}}+{{y}^{2}}-2x-2y=0$
4) ${{x}^{2}}+{{y}^{2}}+2x+2y=0$
Solution: Explanation: No Explanation
System of circles

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