circle

Question: The equation of the normal to the circle ${{x}^{2}}+{{y}^{2}}=9$ at the point $\left( \frac{1}{\sqrt{2}},\frac{1}{\sqrt{2}} \right)$ is



1) $x+y=0$
2) $x-y=\frac{\sqrt{2}}{3}$
3) $x-y=0$
4) None of these
Solution: Explanation: No Explanation
Tangent and normal to a circle

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