circle

Question: $y-x+3=0$ is the equation of normal at $\left( 3+\frac{3}{\sqrt{2}},\frac{3}{\sqrt{2}} \right)$ to which of the following circles

1) ${{\left( x-3-\frac{3}{\sqrt{2}} \right)}^{2}}+{{\left( y-\frac{\sqrt{3}}{2} \right)}^{2}}=9$

2) ${{\left( x-3-\frac{3}{\sqrt{2}} \right)}^{2}}+{{y}^{2}}=6$

3) ${{(x-3)}^{2}}+{{y}^{2}}=9$

4) ${{(x-3)}^{2}}+{{(y-3)}^{2}}=9$

Solution:

Explanation: No Explanation

Tangent and normal to a circle

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