inv-trig

Question: If ${{\sin }^{-1}}(1-x)-2{{\sin }^{-1}}x=\pi /2$, then x equals



1) $\left( 0,\,-\frac{1}{2} \right)$
2) $\left( \frac{1}{2},\,0 \right)$
3) {0}
4) (–1,0)
Solution: Explanation: No Explanation
Inverse trigonometric functions

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