inv-trig

Question: If ${{\cos }^{-1}}x-{{\cos }^{-1}}\frac{y}{2}=\alpha $, then $4{{x}^{2}}-4xy\cos \alpha +{{y}^{2}}$ is equal to



1) $4{{\sin }^{2}}\alpha $
2) $-4{{\sin }^{2}}\alpha $
3) $2\sin 2\alpha $
4) $4$
Solution: Explanation: No Explanation
Inverse trigonometric functions

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