inv-trig

Question: If $3{{\sin }^{-1}}\frac{2x}{1-{{x}^{2}}}-4{{\cos }^{-1}}\frac{1-{{x}^{2}}}{1+{{x}^{2}}}+2{{\tan }^{-1}}\frac{2x}{1-{{x}^{2}}}=\frac{\pi }{3}$ then $x$ =



1) $\sqrt{3}$
2) $\frac{1}{\sqrt{3}}$
3) 1
4) None of these
Solution: Explanation: No Explanation
Inverse trigonometric functions

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