inv-trig

Question: $\tan \left[ \frac{1}{2}{{\sin }^{-1}}\left( \frac{2a}{1+{{a}^{2}}} \right)+\frac{1}{2}{{\cos }^{-1}}\left( \frac{1-{{a}^{2}}}{1+{{a}^{2}}} \right) \right]=$



1) $\frac{2a}{1+{{a}^{2}}}$
2) $\frac{1-{{a}^{2}}}{1+{{a}^{2}}}$
3) $\frac{2a}{1-{{a}^{2}}}$
4) None of these
Solution: Explanation: No Explanation
Inverse trigonometric functions

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