inv-trig

Question: ${{\tan }^{-1}}\frac{3}{4}+{{\tan }^{-1}}\frac{3}{5}-{{\tan }^{-1}}\frac{8}{19}=$



1) $\frac{\pi }{4}$
2) $\frac{\pi }{3}$
3) $\frac{\pi }{6}$
4) None of these
Solution: Explanation: No Explanation
Inverse trigonometric functions

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