inv-trig

Question: If ${{\cot }^{-1}}\alpha +{{\cot }^{-1}}\beta ={{\cot }^{-1}}x,$then $x=$



1) $\alpha +\beta $
2) $\alpha -\beta $
3) $\frac{1+\alpha \beta }{\alpha +\beta }$
4) $\frac{\alpha \beta -1}{\alpha +\beta }$
Solution: Explanation: No Explanation
Inverse trigonometric functions

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