inv-trig

Question: ${{\tan }^{-1}}\frac{a-b}{1+ab}+{{\tan }^{-1}}\frac{b-c}{1+bc}=$

1) ${{\tan }^{-1}}a-{{\tan }^{-1}}b$

2) ${{\tan }^{-1}}a-{{\tan }^{-1}}c$

3) ${{\tan }^{-1}}b-{{\tan }^{-1}}c$

4) ${{\tan }^{-1}}c-{{\tan }^{-1}}a$

Solution:

Explanation: No Explanation

Inverse trigonometric functions

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