inv-trig

Question: If ${{\tan }^{-1}}\frac{x-1}{x+2}+{{\tan }^{-1}}\frac{x+1}{x+2}=\frac{\pi }{4}$, then $x =$



1) $\frac{1}{\sqrt{2}}$
2) $-\frac{1}{\sqrt{2}}$
3) $\pm \sqrt{\frac{5}{2}}$
4) $\pm \frac{1}{2}$
Solution: Explanation: No Explanation
Inverse trigonometric functions

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