inv-trig

Question: If $\sin ({{\cot }^{-1}}(x+1)=\cos ({{\tan }^{-1}}x)$, then x =



1) $-\frac{1}{2}$
2) $\frac{1}{2}$
3) 0
4) $\frac{9}{4}$
Solution: Explanation: No Explanation
Inverse trigonometric functions

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