inv-trig

Question: $\sin \left[ \frac{\pi }{2}-{{\sin }^{-1}}\left( -\frac{\sqrt{3}}{2} \right) \right]=$



1) $\frac{\sqrt{3}}{2}$
2) $-\frac{\sqrt{3}}{2}$
3) $\frac{1}{2}$
4) $-\frac{1}{2}$
Solution: Explanation: No Explanation
Inverse trigonometric functions

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