inv-trig

Question: If $\sin \left( {{\sin }^{-1}}\frac{1}{5}+{{\cos }^{-1}}x \right)=1$,then x is equal to



1) 1
2) 0
3) $\frac{4}{5}$
4) $\frac{1}{5}$
Solution: Explanation: No Explanation
Inverse trigonometric functions

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