inv-trig

Question: $1+{{\cot }^{2}}({{\sin }^{-1}}x)=$



1) $\frac{1}{2x}$
2) ${{x}^{2}}$
3) $\frac{1}{{{x}^{2}}}$
4) $\frac{2}{x}$
Solution: Explanation: No Explanation
Inverse trigonometric functions

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