trigonometry

Question: In a triangle $ABC,$ $a=4,b=3$ , $\angle A={{60}^{o}}$. Then c is the root of the equation



1) ${{c}^{2}}-3c-7=0$
2) ${{c}^{2}}+3c+7=0$
3) ${{c}^{2}}-3c+7=0$
4) ${{c}^{2}}+3c-7=0$
Solution: Explanation: No Explanation
Relation between sides and angles Solutions of triangles

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