trigonometry

Question: If $\sin \theta =\sqrt{3}\cos \theta ,-\pi <\theta <0$, then $\theta =$

1) $-\frac{5\pi }{6}$

2) $-\frac{4\pi }{6}$$$

3) $\frac{4\pi }{6}$

4) $\frac{5\pi }{6}$

Solution:

Explanation: No Explanation

Solution of trigonometric equations

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)