If $\cos heta =\frac{8}{17}$ and $ heta $ lies in the 1st quadrant, then the value of $\cos (30{}^\circ + heta )+\cos (45{}^\circ - heta )+\cos (120{}^\circ - heta )$ is

Question

If $\cos 	heta =\frac{8}{17}$ and $	heta $ lies in the 1st quadrant, then the value of $\cos (30{}^\circ +	heta )+\cos (45{}^\circ -	heta )+\cos (120{}^\circ -	heta )$ is

Accepted Answer

$\frac{23}{17}\left( \frac{\sqrt{3}-1}{2}+\frac{1}{\sqrt{2}} \right)$

Answer

$\frac{23}{17}\left( \frac{\sqrt{3}+1}{2}+\frac{1}{\sqrt{2}} \right)$

Answer

$\frac{23}{17}\left( \frac{\sqrt{3}-1}{2}-\frac{1}{\sqrt{2}} \right)$

Answer

$\frac{23}{17}\left( \frac{\sqrt{3}+1}{2}-\frac{1}{\sqrt{2}} \right)$

trigonometry

Question: If $\cos \theta =\frac{8}{17}$ and $\theta $ lies in the 1st quadrant, then the value of $\cos (30{}^\circ +\theta )+\cos (45{}^\circ -\theta )+\cos (120{}^\circ -\theta )$ is

trigonometry

Question: If $\cos \theta =\frac{8}{17}$ and $\theta $ lies in the 1st quadrant, then the value of $\cos (30{}^\circ +\theta )+\cos (45{}^\circ -\theta )+\cos (120{}^\circ -\theta )$ is

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