trigonometry

Question: If $\tan \theta +\sec \theta ={{e}^{x}},$then $\cos \theta $ equals



1) $\frac{({{e}^{x}}+{{e}^{-x}})}{2}$
2) $\frac{2}{({{e}^{x}}+{{e}^{-x}})}$
3) $\frac{({{e}^{x}}-{{e}^{-x}})}{2}$
4) $\frac{({{e}^{x}}-{{e}^{-x}})}{({{e}^{x}}+{{e}^{-x}})}$
Solution: Explanation: No Solution
Fundamental trigonometrical ratios and functions Trigonometrical ratio of allied angles

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