trigonometry

Question: If $\sin A=\frac{4}{5}$and $\cos B=-\frac{12}{13},$where A and B lie in first and third quadrant respectively, then $\cos (A+B)=$



1) $\frac{56}{65}$
2) $-\frac{56}{65}$
3) $\frac{16}{65}$
4) – $\frac{16}{65}$
Solution: Explanation: No Solution
Trigonometric ratios of sum and difference of two and three

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