Categories > trigonometry > Fundamental trigonometrical ratios and functions > If $x\sin 45{}^\circ {{\cos }^{2}}60{}^\circ =\frac{{{\tan }^{2}}60{}^\circ \text{cosec}30{}^\circ }{\sec 45{}^\circ {{\cot }^{2}}30{}^\circ },$ then $x=$

trigonometry

Question: If $x\sin 45{}^\circ {{\cos }^{2}}60{}^\circ =\frac{{{\tan }^{2}}60{}^\circ \text{cosec}30{}^\circ }{\sec 45{}^\circ {{\cot }^{2}}30{}^\circ },$ then $x=$


1) 2
2) 4
3) 8
4) 16
Solution: Explanation: No Solution
Fundamental trigonometrical ratios and functions Trigonometrical ratio of allied angles

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