trigonometry

Question: In $\Delta ABC$ , $(b-c)\cot \frac{A}{2}+(c-a)\cot \frac{B}{2}+(a-b)$ $\cot \frac{C}{2}$ is equal to



1) 0
2) 1
3) $\pm 1$
4) 2
Solution: Explanation: No Explanation
Relation between sides and angles Solutions of triangles

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