Categories > Kinetic Theory of Gases > rms speed > The molecules of a given mass of a gas have a r.m.s. velocity of 200 m/sec at 27°C and $1.0\times {{10}^{5}}\,N/{{m}^{2}}$ pressure. When the temperature is 127°C and pressure is $0.5\times {{10}^{5}}\,N/{{m}^{2}}$, the r.m.s. velocity in m/sec will be

Kinetic Theory of Gases

Question: The molecules of a given mass of a gas have a r.m.s. velocity of 200 m/sec at 27°C and $1.0\times {{10}^{5}}\,N/{{m}^{2}}$ pressure. When the temperature is 127°C and pressure is $0.5\times {{10}^{5}}\,N/{{m}^{2}}$, the r.m.s. velocity in m/sec will be


1) $\frac{100\sqrt{2}}{3}$
2) $100\sqrt{2}$
3) $\frac{400}{\sqrt{3}}$
4) None of the above
Solution: Explanation: No Explanation
rms speed speed of gas

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