Kinetic Theory of Gases

Question: The kinetic energy of one gram molecule of a gas at normal temperature and pressure is$(R=8.31\,J/mole-K)$

1) $0.56\times {{10}^{4}}\,J$

2) $1.3\times {{10}^{2}}\,J$

3) $2.7\times {{10}^{2}}\,J$

4) $3.4\times {{10}^{3}}\,J$

Solution:

Explanation: No Explanation

Pressure and Energy

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