Mechanical Properties of Solids

Question: When a force is applied on a wire of uniform cross-sectional area $3\times {{10}^{-6}}\,{{m}^{2}}$and length 4m, the increase in length is $1 mm$. Energy stored in it will be $(Y=2\times {{10}^{11}}\,N/{{m}^{2}})$



1) 6250 J
2) 0.177 J
3) 0.075 J
4) 0.150 J
Solution: Explanation: No Explanation
Work Done in Stretching a Wire

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