Mechanical Properties of Solids

Question: A steel ring of radius r and cross-section area $A$ is fitted on to a wooden disc of radius $R(R>r)$. If Young's modulus be $E$, then the force with which the steel ring is expanded is

1) $AE\frac{R}{r}$

2) $AE\left( \frac{R-r}{r} \right)$

3) $\frac{E}{A}\left( \frac{R-r}{A} \right)$

4) $\frac{Er}{AR}$

Solution:

Explanation: No Explanation

Young’s Modulus Breaking Stress

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