differentiation

Question: If $y = {({x^x})^x}$, then $\frac{{dy}}{{dx}}$=

1) ${({x^x})^x}(1 + 2\log x)$

2) ${({x^x})^x}(1 + \log x)$

3) $x{({x^x})^x}(1 + 2\log x)$

4) $x\,{({x^x})^x}(1 + \log x)$

Solution:

Explanation: Explanation

Implicit-function

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