differentiation

Question: If ${{a}^{2}}{{x}^{4}}+{{b}^{2}}{{y}^{4}}={{c}^{6}},$ then maximum value of xy is

1) $\frac{{{c}^{2}}}{\sqrt{ab}}$

2) $\frac{{{c}^{3}}}{ab}$

3) $\frac{{{c}^{3}}}{\sqrt{2ab}}$

4) $\frac{{{c}^{3}}}{2ab}$

Solution:

Explanation: No Explanation

Maxima and Minima

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