differentiation

Question: If $\cos x = \frac{1}{{\sqrt {1 + {t^2}} }}$and $\sin y = \frac{t}{{\sqrt {1 + {t^2}} }}$, then $\frac{{dy}}{{dx}} = $



1) –1
2) $\frac{{1 - t}}{{1 + {t^2}}}$
3) $\frac{1}{{1 + {t^2}}}$
4) 1
Solution: Explanation: Explanation
Implicit-function

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