differentiation

Question: If $x = t + \frac{1}{t},y = t - \frac{1}{t},$then $\frac{{{d^2}y}}{{d{x^2}}}$is equal to



1) $ - 4t{({t^2} - 1)^{ - 2}}$
2) $ - 4{t^3}{({t^2} - 1)^{ - 3}}$
3) $({t^2} + 1){({t^2} - 1)^{ - 1}}$
4) $ - 4{t^2}{({t^2} - 1)^{ - 2}}$
Solution: Explanation: Explanation
Implicit-function

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