differentiation

Question: If $\tan y = \frac{{2t}}{{1 - {t^2}}}$and $\sin x = \frac{{2t}}{{1 + {t^2}}},$then $\frac{{dy}}{{dx}} = $

1) $\frac{2}{{1 + {t^2}}}$

2) $\frac{1}{{1 + {t^2}}}$

3) 1

4) 2

Solution:

Explanation: Explanation

Implicit-function

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