differentiation

Question: $x\sqrt {1 + y} + y\sqrt {1 + x} = 0$, then $\frac{{dy}}{{dx}} = $



1) $1 + x$
2) ${(1 + x)^{ - 2}}$
3) $ - {(1 + x)^{ - 1}}$
4) $ - {(1 + x)^{ - 2}}$
Solution: Explanation: Explanation
Implicit-function

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