differentiation

Question: If ${x^m}{y^n} = {(x + y)^{m + n}}$then ${\left. {\frac{{dy}}{{dx}}} \right|_{x = 1,y = 2}}$ is equal to



1) 01-Feb
2) 2
3) 2m/n
4) m/ 2n
Solution: Explanation: Explanation
standard-differentiation

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