Categories > electrochemistry > Electrode potential > $E_{N{{a}^{+}}/Na(s)}^{0}=-2.71\,V$, $E_{M{{g}^{2+}}/Mg(s)}^{0}=-2.37\,V$, $E_{C{{r}^{3+}}/Cr(s)}^{0}=-0.41\,V$. Based on this data, state which of the following is the weakest reducing agent

electrochemistry

Question: $E_{N{{a}^{+}}/Na(s)}^{0}=-2.71\,V$, $E_{M{{g}^{2+}}/Mg(s)}^{0}=-2.37\,V$, $E_{C{{r}^{3+}}/Cr(s)}^{0}=-0.41\,V$. Based on this data, state which of the following is the weakest reducing agent


1) $N{{a}^{+}}$
2) $Na$
3) $Cr$
4) $F{{e}^{2+}}$
Solution: Explanation: No Explanation
Electrode potential Ecell Nernst equation and ECS

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