electrochemistry

Question: The ${{E}^{0}}$ for half cells $Fe/F{{e}^{2+}}$ and $Cu/C{{u}^{2+}}$ are $– 0.44 V$ and $+ 0.32 V$ respectively. Then



1) $C{{u}^{2+}}$ oxidises $Fe$
2) $C{{u}^{2+}}$ oxidises $F{{e}^{2+}}$
3) $Cu$ oxidises $F{{e}^{2+}}$
4) $Cu$ reduces $F{{e}^{2+}}$
Solution: Explanation: No Explanation
Electrode potential Ecell Nernst equation and ECS

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