Categories > electrochemistry > Electrode potential > Electrode potential data are given below : $F{{e}^{3+}}(aq)+{{e}^{-}}\to F{{e}^{-1}}(aq);\,{{E}^{0}}=+0.77\,V$; $A{{l}^{3+}}(aq)+3{{e}^{-}}\to A{{l}^{-1}}(s);\,{{E}^{0}}=-1.66\,V$; $B{{r}_{2}}(aq)+2{{e}^{-}}\to 2B{{r}^{-}}(aq);\,{{E}^{0}}=+1.08\,V$; Based on the data given above, reducing power of $F{{e}^{2+}}$, $Al$ and $B{{r}^{-}}$ will increase in the order

electrochemistry

Question: Electrode potential data are given below : $F{{e}^{3+}}(aq)+{{e}^{-}}\to F{{e}^{-1}}(aq);\,{{E}^{0}}=+0.77\,V$; $A{{l}^{3+}}(aq)+3{{e}^{-}}\to A{{l}^{-1}}(s);\,{{E}^{0}}=-1.66\,V$; $B{{r}_{2}}(aq)+2{{e}^{-}}\to 2B{{r}^{-}}(aq);\,{{E}^{0}}=+1.08\,V$; Based on the data given above, reducing power of $F{{e}^{2+}}$, $Al$ and $B{{r}^{-}}$ will increase in the order


1) $B{{r}^{-}}<F{{e}^{2+}}<Al$
2) $F{{e}^{2+}}<Al<B{{r}^{-}}$
3) $Al<B{{r}^{-}}<F{{e}^{2+}}$
4) $Al<F{{e}^{2+}}<B{{r}^{-}}$
Solution: Explanation: No Explanation
Electrode potential Ecell Nernst equation and ECS

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