Categories > electrochemistry > Conductors and Conductance > The conductivity of a saturated solution of $BaS{{O}_{4}}$ is $3.06\times {{10}^{-6}}\,oh{{m}^{-1}}\,c{{m}^{-1}}$ and its equivalent conductance is $1.53\,Oh{{m}^{-1}}\,c{{m}^{-1}}\,equivalen{{t}^{-1}}$. The ${{K}_{sp}}$ of the $BaS{{O}_{4}}$ will be

electrochemistry

Question: The conductivity of a saturated solution of $BaS{{O}_{4}}$ is $3.06\times {{10}^{-6}}\,oh{{m}^{-1}}\,c{{m}^{-1}}$ and its equivalent conductance is $1.53\,Oh{{m}^{-1}}\,c{{m}^{-1}}\,equivalen{{t}^{-1}}$. The ${{K}_{sp}}$ of the $BaS{{O}_{4}}$ will be


1) $4\times {{10}^{-12}}$
2) $2.5\times {{10}^{-9}}$
3) $2.5\times {{10}^{-13}}$
4) $4\times {{10}^{-6}}$
Solution: Explanation: No Explanation
Conductors and Conductance

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