electrochemistry

Question: $F{{e}^{3+}}(aq)+{{e}^{-}}\to F{{e}^{2+}};\,{{E}^{0}}=+0.77V$; $A{{l}^{3+}}(aq)+3{{e}^{-}}\to Al(s);\,{{E}^{0}}=-1.66V$; $B{{r}_{2}}(aq)+2{{e}^{-}}\to 2B{{r}^{-}}(aq);\,{{E}^{0}}=+1.08V$; Considering the above data, state which of the following represents the correct order of reducing power

1) $B{{r}^{-}}<F{{e}^{2+}}<Al$

2) $F{{e}^{2+}}<Al<B{{r}^{-}}$

3) $Al<B{{r}^{-}}<F{{e}^{2+}}$

4) $Al<F{{e}^{2+}}<B{{r}^{-}}$

Solution:

Explanation: No Explanation

Electrode potential Ecell Nernst equation and ECS

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