electrochemistry

Question: $Emf$ of a cell whose half cells are given below is $M{{g}^{2+}}+2{{e}^{-}}\to Mg\,(s)$; E = – 2.37 V $C{{u}^{2+}}+2{{e}^{-}}\to Cu\,(s)$; E = + 0.33 V

1) – 2.03 V

2) 1.36 V

3) 2.7 V

4) 2.03 V

Solution:

Explanation: No Explanation

Electrode potential Ecell Nernst equation and ECS

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