electrochemistry

Question: The resistance of $0.01 N$ $NaCl$ solution at ${{25}^{o}}C$ is $200 \Omega$. Cell constant of conductivity cell is $1\,c{{m}^{-1}}$. The equivalent conductance is

1) $5\times {{10}^{2}}\,{{\Omega }^{-1}}\,c{{m}^{2}}\,e{{q}^{-1}}$

2) $6\times {{10}^{3}}\,{{\Omega }^{-1}}\,c{{m}^{2}}\,e{{q}^{-1}}$

3) $7\times {{10}^{4}}\,{{\Omega }^{-1}}\,c{{m}^{2}}\,e{{q}^{-1}}$

4) $8\times {{10}^{5}}\,{{\Omega }^{-1}}\,c{{m}^{2}}\,e{{q}^{-1}}$

Solution:

Explanation: No Explanation

Conductors and Conductance

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