differentiation

Question: If $f(1) = 3,\,f'(1) = 2,$then $\frac{d}{{dx}}\{ \log f\,({e^x} + 2x)\} $ at $x = 0$ is



1) 02-Mar
2) 03-Feb
3) 2
4) 0
Solution: Explanation: Explanation
standard-differentiation

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