differentiation

Question: If $y = \sqrt {\sin \sqrt x } $, then $\frac{{dy}}{{dx}} = $

1) $\frac{1}{{2\sqrt {\cos \sqrt x } }}$

2) $\frac{{\sqrt {\cos \sqrt x } }}{{2x}}$

3) $\frac{{\cos \sqrt x }}{{4\sqrt x \sqrt {\sin \sqrt x } }}$

4) $\frac{1}{{2\sqrt {\sin x} }}$

Solution:

Explanation: Explanation

standard-differentiation

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)