differentiation

Question: If $x = a{t^2},y = 2at$, then $\frac{{{d^2}y}}{{d{x^2}}} = $



1) $ - \frac{1}{{{t^2}}}$
2) $\frac{1}{{2a{t^3}}}$
3) $ - \frac{1}{{{t^3}}}$
4) $ - \frac{1}{{2a{t^3}}}$
Solution: Explanation: Explanation
Implicit-function

Rate this question:

Average rating: (0 votes)

Previous Question Next Question