Categories > solutions > Colligative properties > The boiling point of water $({{100}^{o}}C)$ becomes ${{100.52}^{o}}C$. If 3 grams of a nonvolatile solute is dissolved in $200\ ml$ of water. The molecular weight of solute is (${{K}_{b}}$ for water is $0.6\ K-m$)

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Question: The boiling point of water $({{100}^{o}}C)$ becomes ${{100.52}^{o}}C$. If 3 grams of a nonvolatile solute is dissolved in $200\ ml$ of water. The molecular weight of solute is (${{K}_{b}}$ for water is $0.6\ K-m$)


1) $12.2\ g\ mo{{l}^{-1}}$
2) $15.4\ g\ mol$
3) $17.3\ g\ mo{{l}^{-1}}$
4) $20.4\ g\ mol$
Solution: Explanation: No Explanation
Colligative properties

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