Alternating Current

Question: There is a $5\Omega $ resistance in an ac, circuit. Inductance of 0.1H is connected with it in series. If equation of ac e.m.f. is $5\sin 50t$ then the phase difference between current and e.m.f. is

1) $\frac{\pi }{2}$

2) $\frac{\pi }{6}$

3) $\frac{\pi }{4}$

4) $0$

Solution:

Explanation: No Explanation

AC circuits

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