Alternating Current

Question: An inductor of inductance $L$ and resistor of resistance $R$ are joined in series and connected by a source of frequency $\omega $. Power dissipated in the circuit is

1) $\frac{{({R^2} + {\omega ^2}{L^2})}}{V}$

2) $\frac{{{V^2}R}}{{({R^2} + {\omega ^2}{L^2})}}$

3) $\frac{V}{{({R^2} + {\omega ^2}{L^2})}}$

4) $\frac{{\sqrt {{R^2} + {\omega ^2}{L^2}} }}{{{V^2}}}$

Solution:

Explanation: No Explanation

AC circuits

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