differentiation

Question: If $y = \frac{{{e^x}\log x}}{{{x^2}}}$, then $\frac{{dy}}{{dx}} = $

1) $\frac{{{e^x}[1 + (x + 2)\log x]}}{{{x^3}}}$

2) $\frac{{{e^x}[1 - (x - 2)\log x]}}{{{x^4}}}$

3) $\frac{{{e^x}[1 - (x - 2)\log x]}}{{{x^3}}}$

4) $\frac{{{e^x}[1 + (x - 2)\log x]}}{{{x^3}}}$

Solution:

Explanation: Explanation

standard-differentiation

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